a="Roma"; b="Torino"
for x in (3<5, 3<5<7, 3<5<4,
  6==7, 6==6,a=='Roma',a<b):
  print x,
---------------------------------------
for x in (0,1,0.0,[],(),[0],
  None,'','alfa'):
  print "%-6s%s" %(x, bool(x))
---------------------------------------
print (3<4)+0.7
# 1.7

v=[3<4,3<0]
for x in v: print x>0.5,
# True False

print
from rpy import r

a=[True,True,False,True,False]
print r.sum(a)
# 3
---------------------------------------
print 2 and 3 and 8
# 8
print 2 and [] and 7
# []
---------------------------------------
print 0 or '' or []
# []
print 0 or [] or 2 or 5
# 2
---------------------------------------
print bool(2 and 3 and 8)
# True
print bool(2 and [] and 7)
# False

print bool(0 or '' or [])
# False
print bool(0 or [] or 2 or 5)
# True
---------------------------------------
print math.log(0)
# Errore - il logaritmo di 0
# non e' definito.

print 1 or math.log(0)
# 1 - In questo caso il logaritmo
# non viene calcolato.
---------------------------------------
print not []
# True

print not 5
# False
---------------------------------------
def iftern (A,x,y): # if ternario
  if A: return x
  else: return y
---------------------------------------
def f (n): # Brutta sorpresa!
  return iftern(n==0,1,n*f(n-1))
---------------------------------------
x=(1,0,1,0,1,0,1,0,1,0,1,0)
a=(7,None,8,None,9,None)
b=(None,1,None,2)
u=r.ifelse(x,a,b)
print u
# [7, 1, 8, 2, 9, 1, 7, 2, 8, 1, 9, 2]